{"id":4499,"date":"2026-04-01T06:56:01","date_gmt":"2026-04-01T06:56:01","guid":{"rendered":"https:\/\/hydrathpower.com\/?p=4499"},"modified":"2026-04-01T06:56:01","modified_gmt":"2026-04-01T06:56:01","slug":"calculo-da-formula-hidraulica","status":"publish","type":"post","link":"https:\/\/hydrathpower.com\/pt\/hydraulic-formulas-and-calculations-power-flow-force-and-speed-explained\/","title":{"rendered":"F\u00f3rmulas e c\u00e1lculos hidr\u00e1ulicos: Explica\u00e7\u00e3o de pot\u00eancia, fluxo, for\u00e7a e velocidade"},"content":{"rendered":"<h3>O que \u00e9 esta p\u00e1gina?<\/h3>\n<p>Esta p\u00e1gina re\u00fane as f\u00f3rmulas hidr\u00e1ulicas que os engenheiros usam todos os dias. Cada equa\u00e7\u00e3o \u00e9 mostrada com unidades que correspondem \u00e0 pr\u00e1tica do setor, seguida de pequenos exemplos que voc\u00ea pode adaptar ao seu sistema.<\/p>\n<h3>F\u00f3rmulas-chave<\/h3>\n<ul>\n<li>Press\u00e3o-For\u00e7a-\u00c1rea (imperial): p(psi) = F(lbf) \/ A(in\u00b2); F = p \u00d7 A; A = F \/ p<\/li>\n<li>Pot\u00eancia hidr\u00e1ulica: hp = p(psi) \u00d7 Q(gpm) \/ 1714; kW = Q(l\/min) \u00d7 p(bar) \/ 600<\/li>\n<li>Fluxo da bomba: Q(gpm) = n(rpm) \u00d7 D(in\u00b3\/rev) \/ 231; Q(l\/min) = D(cm\u00b3\/rev) \u00d7 n(rpm) \/ 1000<\/li>\n<li>Torque do motor: T(in-lb) = p(psi) \u00d7 D(in\u00b3\/rev) \/ 6,28; T(Nm) = D(cm\u00b3\/rev) \u00d7 p(bar) \/ (20\u03c0)<\/li>\n<li>\u00c1rea do cilindro: A = \u03c0d\u00b2\/4; \u00c1rea lateral da haste = A<sub>pist\u00e3o<\/sub> - A<sub>haste<\/sub><\/li>\n<li>For\u00e7a do cilindro: F = p \u00d7 A<\/li>\n<li>Velocidade do cilindro: v(ft\/min) = 19,25 \u00d7 Q(gpm) \/ A(in\u00b2); ou v = Q\/A em unidades consistentes<\/li>\n<li>Diretriz de velocidade da linha: v(ft\/s) = Q(gpm) \u00d7 0,3208 \/ A(in\u00b2)<\/li>\n<li>Equival\u00eancia de calor: 1 hp = 2545 BTU\/hr \u2248 746 W<\/li>\n<\/ul>\n<h3>Exemplos pr\u00e1ticos<\/h3>\n<ol>\n<li>Pot\u00eancia hidr\u00e1ulica a 150 bar e 20 L\/minPh(kW) = Q \u00d7 p \/ 600 = 20 \u00d7 150 \/ 600 = 5 kW (\u2248 6,7 hp)<\/li>\n<li><a href=\"\/hydraulic-cylinders\/\">Cilindro<\/a> empuxo com furo de 50 mm a 140 bar\u00c1rea = \u03c0 \u00d7 (0,05 m)\u00b2 \/ 4 = 0,001963 m\u00b2For\u00e7a = 14 MPa \u00d7 0,001963 m\u00b2 \u2248 27,5 kN<\/li>\n<li>Torque do motor, D = 25 cm\u00b3\/rev, p = 140 barT = D \u00d7 p \/ (20\u03c0) = 25 \u00d7 140 \/ 62,832 \u2248 55,7 Nm<\/li>\n<li>Verifica\u00e7\u00e3o da velocidade da mangueira, Q = 30 L\/min (\u2248 7,93 gpm), 1\/2 pol. IDA = \u03c0 \u00d7 (0,5 pol.)\u00b2 \/ 4 = 0,196 pol\u00b2v = 7,93 \u00d7 0,3208 \/ 0,196 \u2248 13,0 p\u00e9s\/s<\/li>\n<\/ol>\n<h3>Como dimensionar uma HPU (cinco etapas)<\/h3>\n<ol>\n<li>Defina a tarefa: tempo de ciclo, press\u00e3o de pico, temperatura ambiente.<\/li>\n<li>Calcule a \u00e1rea e a for\u00e7a do atuador a partir da carga necess\u00e1ria; defina a press\u00e3o de projeto com margem de 10-20%.<\/li>\n<li>Derivar o fluxo da \u00e1rea e da velocidade alvo; converter para o deslocamento da bomba com a rpm esperada.<\/li>\n<li>Fa\u00e7a uma estimativa da pot\u00eancia hidr\u00e1ulica a partir de p e Q; aplique a efici\u00eancia geral para selecionar o motor de acionamento.<\/li>\n<li>Verifique a velocidade da linha e a carga de calor; dimensione o reservat\u00f3rio e o resfriamento de acordo.<\/li>\n<\/ol>\n<h3>Perguntas frequentes<\/h3>\n<h4>Qual \u00e9 a f\u00f3rmula da pot\u00eancia hidr\u00e1ulica?<\/h4>\n<p>hp = p(psi) \u00d7 Q(gpm) \/ 1714. Para sistemas m\u00e9tricos, kW = Q(l\/min) \u00d7 p(bar) \/ 600.<\/p>\n<h4>Como fa\u00e7o para calcular a velocidade do cilindro?<\/h4>\n<p>Divida a vaz\u00e3o pela \u00e1rea do pist\u00e3o em unidades consistentes. Em imperial, v(ft\/min) = 19,25 \u00d7 Q(gpm) \/ A(in\u00b2).<\/p>\n<h4>Como fa\u00e7o para encontrar o torque do motor a partir da press\u00e3o e do deslocamento?<\/h4>\n<p>Use T(in-lb) = p(psi) \u00d7 D(in\u00b3\/rev) \/ 6,28 ou T(Nm) = D(cm\u00b3\/rev) \u00d7 p(bar) \/ (20\u03c0).<\/p>\n<h4>Quais s\u00e3o os limites t\u00edpicos de velocidade da mangueira?<\/h4>\n<p>As linhas de press\u00e3o s\u00e3o normalmente mantidas em torno de 10-20 p\u00e9s\/s; as linhas de suc\u00e7\u00e3o s\u00e3o muito mais baixas. Sempre verifique as especifica\u00e7\u00f5es de seus componentes.<\/p>\n<h4>Como posso estimar a carga t\u00e9rmica a partir de uma queda de press\u00e3o?<\/h4>\n<p>Pot\u00eancia perdida (hp) \u2248 \u0394p(psi) \u00d7 Q(gpm) \/ 1714 e, em seguida, converta para BTU\/hr ou watts.<\/p>","protected":false},"excerpt":{"rendered":"<p>What is This Page? This page collects the hydraulic formulas engineers use every day. Each equation is shown with units [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":4505,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center 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center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[1],"tags":[],"class_list":["post-4499","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-uncategorized"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v28.8 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Hydraulic Formulas and Calculations: Power, Flow, Force and Speed Explained - Hydrath Power<\/title>\n<meta name=\"description\" content=\"earn the core hydraulic formulas for power, flow, force and speed, plus pump, motor and cylinder calculations with clear, worked examples.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" 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