{"id":4499,"date":"2026-04-01T06:56:01","date_gmt":"2026-04-01T06:56:01","guid":{"rendered":"https:\/\/hydrathpower.com\/?p=4499"},"modified":"2026-04-01T06:56:01","modified_gmt":"2026-04-01T06:56:01","slug":"hydraulische-formule-berekening","status":"publish","type":"post","link":"https:\/\/hydrathpower.com\/nl\/hydraulic-formulas-and-calculations-power-flow-force-and-speed-explained\/","title":{"rendered":"Hydraulische formules en berekeningen: Uitleg over vermogen, stroming, kracht en snelheid"},"content":{"rendered":"<h3>Wat is deze pagina?<\/h3>\n<p>Deze pagina verzamelt de hydraulische formules die ingenieurs dagelijks gebruiken. Elke vergelijking wordt weergegeven met eenheden die overeenkomen met de praktijk in de industrie, gevolgd door kleine voorbeelden die u kunt aanpassen aan uw systeem.<\/p>\n<h3>Sleutelformules<\/h3>\n<ul>\n<li>Druk-Kracht-Afmeting (imperiaal): p(psi) = F(lbf) \/ A(in\u00b2); F = p \u00d7 A; A = F \/ p<\/li>\n<li>Hydraulisch vermogen: pk = p(psi) \u00d7 Q(gpm) \/ 1714; kW = Q(l\/min) \u00d7 p(bar) \/ 600<\/li>\n<li>Pompdebiet: Q(gpm) = n(tpm) \u00d7 D(in\u00b3\/rev) \/ 231; Q(l\/min) = D(cm\u00b3\/rev) \u00d7 n(tpm) \/ 1000<\/li>\n<li>Motorkoppel: T(in-lb) = p(psi) \u00d7 D(in\u00b3\/omw) \/ 6,28; T(Nm) = D(cm\u00b3\/omw) \u00d7 p(bar) \/ (20\u03c0)<\/li>\n<li>Cilinderoppervlak: A = \u03c0d\u00b2\/4; Oppervlakte stangzijde = A<sub>zuiger<\/sub> - A<sub>staaf<\/sub><\/li>\n<li>Cilinderkracht: F = p \u00d7 A<\/li>\n<li>Cilindersnelheid: v(ft\/min) = 19,25 \u00d7 Q(gpm) \/ A(in\u00b2); of v = Q\/A in consistente eenheden<\/li>\n<li>Richtlijn voor lijnsnelheid: v(ft\/s) = Q(gpm) \u00d7 0,3208 \/ A(in\u00b2)<\/li>\n<li>Warmte-equivalentie: 1 pk = 2545 BTU\/hr \u2248 746 W<\/li>\n<\/ul>\n<h3>Voorbeelden<\/h3>\n<ol>\n<li>Hydraulisch vermogen bij 150 bar en 20 L\/minPh(kW) = Q \u00d7 p \/ 600 = 20 \u00d7 150 \/ 600 = 5 kW (\u2248 6,7 pk)<\/li>\n<li><a href=\"\/hydraulic-cylinders\/\">Cilinder<\/a> stuwkracht met 50 mm boring bij 140 barAfmeting = \u03c0 \u00d7 (0,05 m)\u00b2 \/ 4 = 0,001963 m\u00b2Kracht = 14 MPa \u00d7 0,001963 m\u00b2 \u2248 27,5 kN<\/li>\n<li>Motorkoppel, D = 25 cm\u00b3\/omw, p = 140 barT = D \u00d7 p \/ (20\u03c0) = 25 \u00d7 140 \/ 62,832 \u2248 55,7 Nm<\/li>\n<li>Snelheidscontrole slang, Q = 30 L\/min (\u2248 7,93 gpm), 1\/2 in IDA = \u03c0 \u00d7 (0,5 in)\u00b2 \/ 4 = 0,196 in\u00b2v = 7,93 \u00d7 0,3208 \/ 0,196 \u2248 13,0 ft\/s<\/li>\n<\/ol>\n<h3>De grootte van een HPU bepalen (in vijf stappen)<\/h3>\n<ol>\n<li>Definieer plicht: cyclustijd, piekdruk, omgevingstemperatuur.<\/li>\n<li>Bereken het oppervlak en de kracht van de actuator op basis van de vereiste belasting; stel de ontwerpdruk in met een marge van 10-20%.<\/li>\n<li>Leid het debiet af uit de doelsnelheid en het oppervlak; zet om naar pompverplaatsing met het verwachte toerental.<\/li>\n<li>Maak een schatting van het hydraulisch vermogen op basis van p en Q; pas het totale rendement toe om de aandrijfmotor te selecteren.<\/li>\n<li>Controleer de snelheid van de leiding en de warmtebelasting; pas de grootte van het reservoir en de koeling hierop aan.<\/li>\n<\/ol>\n<h3>Veelgestelde vragen<\/h3>\n<h4>Wat is de formule voor hydraulische paardenkracht?<\/h4>\n<p>pk = p(psi) \u00d7 Q(gpm) \/ 1714. Voor metrische systemen is kW = Q(l\/min) \u00d7 p(bar) \/ 600.<\/p>\n<h4>Hoe bereken ik de cilindersnelheid?<\/h4>\n<p>Deel het debiet door het zuigeroppervlak in consistente eenheden. In imperial, v(ft\/min) = 19,25 \u00d7 Q(gpm) \/ A(in\u00b2).<\/p>\n<h4>Hoe vind ik het motorkoppel uit druk en verplaatsing?<\/h4>\n<p>Gebruik T(in-lb) = p(psi) \u00d7 D(in\u00b3\/rev) \/ 6,28 of T(Nm) = D(cm\u00b3\/rev) \u00d7 p(bar) \/ (20\u03c0).<\/p>\n<h4>Wat zijn typische snelheidslimieten voor slangen?<\/h4>\n<p>Drukleidingen worden gewoonlijk in de buurt van 10-20 ft\/s gehouden; zuigleidingen zijn veel lager. Controleer dit altijd aan de hand van de specificaties van uw componenten.<\/p>\n<h4>Hoe schat ik de warmtebelasting op basis van een drukdaling?<\/h4>\n<p>Verloren vermogen (pk) \u2248 \u0394p(psi) \u00d7 Q(gpm) \/ 1714, vervolgens omrekenen naar BTU\/hr of watt.<\/p>","protected":false},"excerpt":{"rendered":"<p>What is This Page? This page collects the hydraulic formulas engineers use every day. Each equation is shown with units [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":4505,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center 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