{"id":4499,"date":"2026-04-01T06:56:01","date_gmt":"2026-04-01T06:56:01","guid":{"rendered":"https:\/\/hydrathpower.com\/?p=4499"},"modified":"2026-04-01T06:56:01","modified_gmt":"2026-04-01T06:56:01","slug":"calcolo-della-formula-idraulica","status":"publish","type":"post","link":"https:\/\/hydrathpower.com\/it\/hydraulic-formulas-and-calculations-power-flow-force-and-speed-explained\/","title":{"rendered":"Formule e calcoli idraulici: Spiegazione di potenza, portata, forza e velocit\u00e0"},"content":{"rendered":"<h3>Che cos'\u00e8 questa pagina?<\/h3>\n<p>Questa pagina raccoglie le formule idrauliche che gli ingegneri utilizzano quotidianamente. Ogni equazione \u00e8 mostrata con unit\u00e0 di misura che corrispondono alla pratica industriale, seguita da piccoli esempi che possono essere adattati al proprio sistema.<\/p>\n<h3>Formule chiave<\/h3>\n<ul>\n<li>Pressione-Forza-Area (imperiale): p(psi) = F(lbf) \/ A(in\u00b2); F = p \u00d7 A; A = F \/ p<\/li>\n<li>Potenza idraulica: hp = p(psi) \u00d7 Q(gpm) \/ 1714; kW = Q(l\/min) \u00d7 p(bar) \/ 600<\/li>\n<li>Portata della pompa: Q(gpm) = n(rpm) \u00d7 D(in\u00b3\/rev) \/ 231; Q(l\/min) = D(cm\u00b3\/rev) \u00d7 n(rpm) \/ 1000<\/li>\n<li>Coppia del motore: T(in-lb) = p(psi) \u00d7 D(in\u00b3\/giro) \/ 6,28; T(Nm) = D(cm\u00b3\/giro) \u00d7 p(bar) \/ (20\u03c0)<\/li>\n<li>Area del cilindro: A = \u03c0d\u00b2\/4; Area lato stelo = A<sub>pistone<\/sub> - A<sub>asta<\/sub><\/li>\n<li>Forza del cilindro: F = p \u00d7 A<\/li>\n<li>Velocit\u00e0 del cilindro: v(ft\/min) = 19,25 \u00d7 Q(gpm) \/ A(in\u00b2); o v = Q\/A in unit\u00e0 coerenti<\/li>\n<li>Velocit\u00e0 di linea: v(ft\/s) = Q(gpm) \u00d7 0,3208 \/ A(in\u00b2)<\/li>\n<li>Equivalenza termica: 1 CV = 2545 BTU\/ora \u2248 746 W<\/li>\n<\/ul>\n<h3>Esempi di lavoro<\/h3>\n<ol>\n<li>Potenza idraulica a 150 bar e 20 L\/minPh(kW) = Q \u00d7 p \/ 600 = 20 \u00d7 150 \/ 600 = 5 kW (\u2248 6,7 CV)<\/li>\n<li><a href=\"\/hydraulic-cylinders\/\">Cilindro<\/a> spinta con foro da 50 mm a 140 barArea = \u03c0 \u00d7 (0,05 m)\u00b2 \/ 4 = 0,001963 m\u00b2Forza = 14 MPa \u00d7 0,001963 m\u00b2 \u2248 27,5 kN<\/li>\n<li>Coppia del motore, D = 25 cm\u00b3\/giro, p = 140 barT = D \u00d7 p \/ (20\u03c0) = 25 \u00d7 140 \/ 62,832 \u2248 55,7 Nm<\/li>\n<li>Verifica della velocit\u00e0 del tubo, Q = 30 L\/min (\u2248 7,93 gpm), 1\/2 in IDA = \u03c0 \u00d7 (0,5 in)\u00b2 \/ 4 = 0,196 in\u00b2v = 7,93 \u00d7 0,3208 \/ 0,196 \u2248 13,0 ft\/s<\/li>\n<\/ol>\n<h3>Come dimensionare un'unit\u00e0 HPU (cinque passi)<\/h3>\n<ol>\n<li>Definire il servizio: tempo di ciclo, pressione di picco, temperatura ambiente.<\/li>\n<li>Calcolare l'area e la forza dell'attuatore dal carico richiesto; impostare la pressione di progetto con un margine di 10-20%.<\/li>\n<li>Derivare la portata dalla velocit\u00e0 e dall'area target; convertire in cilindrata della pompa con il numero di giri previsto.<\/li>\n<li>Stimare la potenza idraulica da p e Q; applicare l'efficienza complessiva per selezionare il motore di azionamento.<\/li>\n<li>Controllare la velocit\u00e0 della linea e il carico termico; dimensionare il serbatoio e il raffreddamento di conseguenza.<\/li>\n<\/ol>\n<h3>Domande frequenti<\/h3>\n<h4>Qual \u00e8 la formula della potenza idraulica?<\/h4>\n<p>hp = p(psi) \u00d7 Q(gpm) \/ 1714. Per i sistemi metrici, kW = Q(l\/min) \u00d7 p(bar) \/ 600.<\/p>\n<h4>Come si calcola la velocit\u00e0 del cilindro?<\/h4>\n<p>Dividere la portata per l'area del pistone in unit\u00e0 coerenti. In termini imperiali, v(ft\/min) = 19,25 \u00d7 Q(gpm) \/ A(in\u00b2).<\/p>\n<h4>Come si trova la coppia del motore a partire dalla pressione e dalla cilindrata?<\/h4>\n<p>Utilizzare T(in-lb) = p(psi) \u00d7 D(in\u00b3\/rev) \/ 6,28 o T(Nm) = D(cm\u00b3\/rev) \u00d7 p(bar) \/ (20\u03c0).<\/p>\n<h4>Quali sono i limiti di velocit\u00e0 tipici dei tubi?<\/h4>\n<p>Le linee di pressione sono generalmente mantenute intorno ai 10-20 ft\/s; le linee di aspirazione sono molto pi\u00f9 basse. Verificare sempre le specifiche del componente.<\/p>\n<h4>Come si fa a stimare il carico termico da una perdita di pressione?<\/h4>\n<p>Potenza persa (hp) \u2248 \u0394p(psi) \u00d7 Q(gpm) \/ 1714, quindi convertire in BTU\/ora o watt.<\/p>","protected":false},"excerpt":{"rendered":"<p>What is This Page? This page collects the hydraulic formulas engineers use every day. Each equation is shown with units [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":4505,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center 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center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[1],"tags":[],"class_list":["post-4499","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-uncategorized"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v28.8 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Hydraulic Formulas and Calculations: Power, Flow, Force and Speed Explained - Hydrath Power<\/title>\n<meta name=\"description\" content=\"earn the core hydraulic formulas for power, flow, force and speed, plus pump, motor and cylinder calculations with clear, worked examples.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" 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