{"id":4499,"date":"2026-04-01T06:56:01","date_gmt":"2026-04-01T06:56:01","guid":{"rendered":"https:\/\/hydrathpower.com\/?p=4499"},"modified":"2026-04-01T06:56:01","modified_gmt":"2026-04-01T06:56:01","slug":"calcul-de-la-formule-hydraulique","status":"publish","type":"post","link":"https:\/\/hydrathpower.com\/fr\/hydraulic-formulas-and-calculations-power-flow-force-and-speed-explained\/","title":{"rendered":"Formules et calculs hydrauliques : Explication de la puissance, du d\u00e9bit, de la force et de la vitesse"},"content":{"rendered":"<h3>Qu'est-ce que cette page ?<\/h3>\n<p>Cette page rassemble les formules hydrauliques utilis\u00e9es quotidiennement par les ing\u00e9nieurs. Chaque \u00e9quation est pr\u00e9sent\u00e9e avec des unit\u00e9s correspondant aux pratiques de l'industrie, suivies de petits exemples que vous pouvez adapter \u00e0 votre syst\u00e8me.<\/p>\n<h3>Formules cl\u00e9s<\/h3>\n<ul>\n<li>Pression-Force-Surface (imp\u00e9rial) : p(psi) = F(lbf) \/ A(in\u00b2) ; F = p \u00d7 A ; A = F \/ p<\/li>\n<li>Puissance hydraulique : hp = p(psi) \u00d7 Q(gpm) \/ 1714 ; kW = Q(l\/min) \u00d7 p(bar) \/ 600<\/li>\n<li>D\u00e9bit de la pompe : Q(gpm) = n(rpm) \u00d7 D(in\u00b3\/rev) \/ 231 ; Q(l\/min) = D(cm\u00b3\/rev) \u00d7 n(rpm) \/ 1000<\/li>\n<li>Couple du moteur : T(in-lb) = p(psi) \u00d7 D(in\u00b3\/rev) \/ 6,28 ; T(Nm) = D(cm\u00b3\/rev) \u00d7 p(bar) \/ (20\u03c0)<\/li>\n<li>Surface du cylindre : A = \u03c0d\u00b2\/4 ; Surface du c\u00f4t\u00e9 de la tige = A<sub>piston<\/sub> - A<sub>tige<\/sub><\/li>\n<li>Force du cylindre : F = p \u00d7 A<\/li>\n<li>Vitesse du cylindre : v(ft\/min) = 19,25 \u00d7 Q(gpm) \/ A(in\u00b2) ; ou v = Q\/A en unit\u00e9s constantes<\/li>\n<li>Ligne directrice concernant la vitesse de la conduite : v(ft\/s) = Q(gpm) \u00d7 0,3208 \/ A(in\u00b2)<\/li>\n<li>\u00c9quivalence thermique : 1 hp = 2545 BTU\/hr \u2248 746 W<\/li>\n<\/ul>\n<h3>Exemples pratiques<\/h3>\n<ol>\n<li>Puissance hydraulique \u00e0 150 bar et 20 L\/minPh(kW) = Q \u00d7 p \/ 600 = 20 \u00d7 150 \/ 600 = 5 kW (\u2248 6,7 hp)<\/li>\n<li><a href=\"\/hydraulic-cylinders\/\">Cylindre<\/a> pouss\u00e9e avec un al\u00e9sage de 50 mm \u00e0 140 barSurface = \u03c0 \u00d7 (0,05 m)\u00b2 \/ 4 = 0,001963 m\u00b2Force = 14 MPa \u00d7 0,001963 m\u00b2 \u2248 27,5 kN<\/li>\n<li>Couple moteur, D = 25 cm\u00b3\/rev, p = 140 barT = D \u00d7 p \/ (20\u03c0) = 25 \u00d7 140 \/ 62,832 \u2248 55,7 Nm<\/li>\n<li>V\u00e9rification de la vitesse du tuyau, Q = 30 L\/min (\u2248 7,93 gpm), 1\/2 in IDA = \u03c0 \u00d7 (0,5 in)\u00b2 \/ 4 = 0,196 in\u00b2v = 7,93 \u00d7 0,3208 \/ 0,196 \u2248 13,0 ft\/s<\/li>\n<\/ol>\n<h3>Comment dimensionner une HPU (en cinq \u00e9tapes)<\/h3>\n<ol>\n<li>D\u00e9finir les t\u00e2ches : dur\u00e9e du cycle, pression maximale, temp\u00e9rature ambiante.<\/li>\n<li>Calculer la surface et la force de l'actionneur \u00e0 partir de la charge requise ; fixer la pression de calcul avec une marge de 10-20%.<\/li>\n<li>D\u00e9terminer le d\u00e9bit \u00e0 partir de la vitesse cible et de la surface ; convertir la cylindr\u00e9e de la pompe en fonction du r\u00e9gime pr\u00e9vu.<\/li>\n<li>Estimer la puissance hydraulique \u00e0 partir de p et Q ; appliquer le rendement global pour s\u00e9lectionner le moteur d'entra\u00eenement.<\/li>\n<li>V\u00e9rifier la vitesse de la ligne et la charge thermique ; dimensionner le r\u00e9servoir et le refroidissement en cons\u00e9quence.<\/li>\n<\/ol>\n<h3>Questions fr\u00e9quemment pos\u00e9es<\/h3>\n<h4>Quelle est la formule de calcul de la puissance hydraulique ?<\/h4>\n<p>hp = p(psi) \u00d7 Q(gpm) \/ 1714. Pour les syst\u00e8mes m\u00e9triques, kW = Q(l\/min) \u00d7 p(bar) \/ 600.<\/p>\n<h4>Comment calculer la vitesse du cylindre ?<\/h4>\n<p>Diviser le d\u00e9bit par la surface du piston en unit\u00e9s coh\u00e9rentes. En unit\u00e9s imp\u00e9riales, v(ft\/min) = 19,25 \u00d7 Q(gpm) \/ A(in\u00b2).<\/p>\n<h4>Comment calculer le couple moteur \u00e0 partir de la pression et de la cylindr\u00e9e ?<\/h4>\n<p>Utilisez T(in-lb) = p(psi) \u00d7 D(in\u00b3\/rev) \/ 6,28 ou T(Nm) = D(cm\u00b3\/rev) \u00d7 p(bar) \/ (20\u03c0).<\/p>\n<h4>Quelles sont les limites de vitesse typiques des tuyaux ?<\/h4>\n<p>Les conduites de pression sont g\u00e9n\u00e9ralement maintenues \u00e0 environ 10-20 pieds\/s ; les conduites d'aspiration sont beaucoup plus basses. V\u00e9rifiez toujours par rapport aux sp\u00e9cifications de vos composants.<\/p>\n<h4>Comment estimer la charge thermique \u00e0 partir d'une chute de pression ?<\/h4>\n<p>Puissance perdue (hp) \u2248 \u0394p(psi) \u00d7 Q(gpm) \/ 1714, puis convertir en BTU\/hr ou en watts.<\/p>","protected":false},"excerpt":{"rendered":"<p>What is This Page? This page collects the hydraulic formulas engineers use every day. Each equation is shown with units [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":4505,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center 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